2

Say if I have 

s=np.zeros((5,5))
array([[ 0.,  0.,  0.,  0.,  0.],
       [ 0.,  0.,  0.,  0.,  0.],
       [ 0.,  0.,  0.,  0.,  0.],
       [ 0.,  0.,  0.,  0.,  0.],
       [ 0.,  0.,  0.,  0.,  0.]])  #which is an ndarray

s2=[s[ix,1] for ix in range(2,5)],[s[ix2,1] for ix2 in range(2,5)]
([0.0, 0.0, 0.0], [0.0, 0.0, 0.0]) #which is a tuple

How can I make s2 into an array or ndarray? Thank you in advance.

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  • what is "array"? What shape should the result have? have you tried numpy.concatenate()? Commented Nov 11, 2013 at 3:12
  • 1
    Does numpy.array(s2) not give you what you want? Commented Nov 11, 2013 at 3:12
  • Why is it a tuple? You used a list comprehension to build it. Commented Nov 11, 2013 at 4:15

1 Answer 1

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4

Do the obvious, use np.array()

s2 = np.array(s2)
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