Checking if number is within range not working in PHP?

Question

I'm using this code:

if (($height/$width) > 0.5 && ($height/$width) < 0.8) {
  // do stuff
}

For a particular image, $height/$width evaluates to 0.66543438077634 (1080/1623). And yet this appears to be evaluating as false. Can anyone suggest why?

Have you tried to parse float the height and width before the comparison? Somehing like: if ((floatval($height)/floatval($width)) > 0.5) ... — newpatriks
– newpatriks, Commented Nov 15, 2013 at 9:33

Adam · Accepted Answer · 2013-11-15 09:35:55Z

2

Propably You have some problem someware else because this code works fine:

<?
    $height = 1080;
    $width = 1623;
    if (($height/$width) > 0.5 && ($height/$width) < 0.8) {
        echo 'IT WORKS';
    }
    var_dump(($height/$width));
?>

SEE WORKING CODE!

answered Nov 15, 2013 at 9:35

Adam

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1 Comment

NaOH Over a year ago

Yes, this was a different issue... Wasn't testing well enough. Sorry!

GautamD31 · Accepted Answer · 2013-11-15 09:38:51Z

0

Try it like

$div = (float)($height/$width);
if ( $div > 0.5 && $div < 0.8) {
  // do stuff
}

Or you can use

$div = (float)($height)/(float)($width);

edited Nov 15, 2013 at 9:38

answered Nov 15, 2013 at 9:31

GautamD31

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1 Comment

NaOH Over a year ago

No dice... Still false.

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