I would like to create a lazy-seq containing another lazy-seq using clojure.
The data structure that I aready have is a lazy-seq of map and it looks like this:
({:a 1 :b 1})
Now I would like to put that lazy-seq into another one so that the result would be a lazy-seq of a lazy-seq of map:
(({:a 1 :b 1}))
Does anyone know how to do this? Any help would be appreciated
Regards,
Here is an example of creating a list containing a list of maps:
=> (list (list {:a 1 :b 1}))
(({:a 1, :b 1}))
It's not lazy, but you can make both lists lazy with lazy-seq macro:
=> (lazy-seq (list (lazy-seq (list {:a 1 :b 1}))))
or the same code with -> macro:
=> (-> {:a 1 :b 1} list lazy-seq list lazy-seq)
Actually, if you'll replace lists here with vectors you'll get the same result:
=> (lazy-seq [(lazy-seq [{:a 1 :b 1}])])
(({:a 1, :b 1}))
I'm not sure what you're trying to do and why do you want both lists to be lazy. So, provide better explanation if you want further help.
generally, there's nothing special about having a lazy-seq containing many lazy-seq's, so i dont understand exactly what it is you are really after.
you could always do
(map list '({:a 1 :b 1})) ;; gives (({:a 1, :b 1}))
we can even verify that it maintains laziness:
(def a
(concat
(take 5 (repeat {:a 1 :b 2}))
(lazy-seq
(throw (Exception. "too eager")))))
(println (take 5 (map list a))) ;; works fine
(println (take 6 (map list a))) ;; throws an exception
