Invalid conversion from int to int c++?

Question

I declared this function :

int dice(int roll[8]) {
blah blah
return (score);

And called it in int main:

newScore = score(roll[8]);

I am getting an invalid conversion from int to int error. What am I doing wrong? The error is on the line where I call it.

1) dice has no closing brackets 2) What's score? 3) The "blah blah" section is important because without it, we can't tell you what's wrong with your code. — RouteMapper
– RouteMapper, Commented Nov 19, 2013 at 3:19
The error points to the fact that you are expecting an array but passing an integer. What you actually want to pass I can't tell - I personally really don't like declaring a function with a "fixed size array" because you may write code that expects this size, then change your mind when you call it. Better keep these things variable - int dice(int *roll, int n) — Floris
– Floris, Commented Nov 19, 2013 at 3:23

None · Accepted Answer · 2013-11-19 03:25:10Z

3

int dice(int roll[8]);

int roll[8];
int newScore = dice(roll);

This is how arrays are "passed" as arguments.

What happens is dice() receives an int* (which may happen to not point to an array of size 8!) and when using roll as an argument, it "decays" into a pointer to its first element.

edited Nov 19, 2013 at 3:25

answered Nov 19, 2013 at 3:19

None

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