Split flat array into two arrays based on value

Question

I have a PHP array that I am trying to split into 2 different arrays. I am trying to pull out any values that contain the word "hidden". So one array would contain all the values that do not contain the word "hidden". The other array would contain all the values that do contain the word "hidden". I just can't figure out how to do it though.

The original array is coming from a form post that contains keys and values from a bunch of check boxes and hidden inputs. so the actual post value looks something like this:

Group1 => Array([0] => item1,[1] => item2hidden,[2] => item3,[3] => item4,[4] => item5hidden)

so to simplify it:

$myArray = Array(item1, item2hidden, item3, item4, item5hidden)

final output

$arr1 = (item1, item3, item4)
$arr2 = (item2hidden, item5hidden)

Anyone know how to do something like this?

Giacomo1968 · Accepted Answer · 2022-04-07 00:31:29Z

30

You can use array_filter() function:

$myArray = array('item1', 'item2hidden', 'item3', 'item4', 'item5hidden');

$arr1 = array_filter($myArray, function($v) { return strpos($v, 'hidden') === false; });
$arr2 = array_diff($myArray, $arr1);

edited Apr 7, 2022 at 0:31

Giacomo1968

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answered Nov 20, 2013 at 14:18

Glavić

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4 Comments

Narek Over a year ago

Need to be === false; instead of == false;

andnik Over a year ago

Doesn't work if you have array values inside your initial array. For instance, $myArray = [['id' => 1], ['id'] => 2];

Glavić Over a year ago

@andnik: just replace strpos($v, ...to strpos($v['id'], ...

andnik Over a year ago

@Glavić, thanks, but I'm referring to second part. array_diff doesn't work when you are using multidimensional array. This link seems to contain answer I was looking for: stackoverflow.com/questions/11821680/…

Vlad Preda · Accepted Answer · 2013-11-20 14:17:50Z

10

This should do the trick:

$myArray = array('item1', 'item2hidden', 'item3', 'item4', 'item5hidden');
$secondaryArray = array();

foreach ($myArray as $key => $value) {
    if (strpos($value, "hidden") !== false) {
        $secondaryArray[] = $value;
        unset($myArray[$key]);
    }
}

It moves all the entries that contain "hidden" from the $myArray to $secondaryArray.

Note: It's case sensitive

answered Nov 20, 2013 at 14:17

Vlad Preda

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Comments

Viacheslav Kondratiuk · Accepted Answer · 2013-11-20 14:18:47Z

0

$myArray = Array('item1', 'item2hidden', 'item3', 'item4', 'item5hidden');
$arr1 = array();
$arr2 = array();    
foreach ($myArray as $item) {
    if (strpos($item, "hidden") !== false) {
        $arr1[] = $item;
    } else {
        $arr2[] = $item;
    }
}

This solution checks if 'hidden' present at current item, if no, move to $arr1 else to $arr2

answered Nov 20, 2013 at 14:18

Viacheslav Kondratiuk

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Comments

Nikolay Krasnov · Accepted Answer · 2013-11-20 14:24:20Z

0

You can use array_filter:

function filtreHiddens($e) {
    if (isset($e['hidden']) && $e['hidden']) return true;
    else return false;
}

function filtreNotHiddens($e) {
    if (isset($e['hidden']) && !$e['hidden']) return true;
    else return false;
}

$arrayToFiltre = array(
    array('hidden' => true, 'someKey' => 'someVal'),
    array('hidden' => false, 'someKey1' => 'someVal1'),
    array('hidden' => true, 'someKey2' => 'someVal3'),
);

$hidden = array_filter($arrayToFiltre, 'filtreHiddens');
$notHidden = array_filter($arrayToFiltre, 'filtreNotHiddens');

print_r($hidden);
print_r($notHidden);

answered Nov 20, 2013 at 14:24

Nikolay Krasnov

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Comments

fresbeeplayer · Accepted Answer · 2013-11-20 14:42:28Z

0

Maybe it's just me, but I would go for the clarity of regular expressions...

foreach($myArray as $item) {
    if (preg_match("/hidden$/i", $item)) {
        array_push($arr2, $item);
    } else {
        array_push($arr1, $item);
    }
}

answered Nov 20, 2013 at 14:42

fresbeeplayer

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