new to java regex, how to grab this part of the string

Question

I have a string that looks like:

http://www.example.com/index.do/blah/1_44/asdf/asdf/asdf
http://www.example.com/index.do/blah/1_44_2342/asdf/asdf/asdf

I need to grab the value 44 from the above, ofcourse '44' could be any number. The number '44' always is prefixed with a _, and after it could be another _ or /.

I have no idea of the java regex API, so as guidance would be appreciated!

cletus · Accepted Answer · 2010-01-06 02:01:05Z

5

It's primarily the Pattern and Matcher classes you're interested in.

String url = "http://www.example.com/index.do/blah/1_44/asdf/asdf/asdf";
Pattern p = Pattern.compile("_(\\d+)");
Matcher m = p.matcher(url);
if (m.find()) {
  int number = Integer.valueOf(m.group(1));
}

This pattern finds the first sequence of one or more digits after the first _.

answered Jan 6, 2010 at 2:01

cletus

627k169 gold badges922 silver badges945 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

new to java regex, how to grab this part of the string

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related