Laravel 4 how to return multiple view data with ajax and json?

Question

Basically I'm trying to make a popup using this ajax:

$.ajax({
    type: 'GET'
    url: 'news/read'
    dataType: 'json'
    cache: false
    timeout: 10000
}).done (msg) ->
    $("article#pop-read").empty().html msg.view
    processing = false
    window.history.pushState
        path: msg.url
        , "", msg.url
    false

And I'm returning a view value and it's url with this:

$data = json_encode(array(
        'view' => View::make('layouts.read'),
    'url' => 'news/read/2013/11/24/test-title-seperate-with-dash'
));
return $data;

This all works really well except that I can't get the view value from laravel (it returns Object object in javascript). But it returns nicely if I directly write it like return View::make('layouts.read'). Why is that?

Additionally (don't have to answer, not primary question), the back button on my browser doesn't work when I use pushState, is it a bug?

The Alpha · Accepted Answer · 2013-11-24 16:34:24Z

14

You may try this

$data = json_encode(array(
    'view' => (String)View::make('layouts.read'),
    'url' => 'news/read/2013/11/24/test-title-seperate-with-dash'
));
return $data;

Also, you can use

View::make('layouts.read')->render();
View::make('layouts.read')->__toString();

Also, Laravel provides Response::json() method for same reason (instead of json_encode).

edited Nov 24, 2013 at 16:34

answered Nov 24, 2013 at 16:26

The Alpha

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3 Comments

user2002495 Over a year ago

ok, thanks, all solutions worked. Moving on to pushState problem now.

Lucabro Over a year ago

any idea how to parse the view into the json response? how to give the html of the view to an element in my page using $('#element').html(data.html) ?

The Alpha Over a year ago

Post a question, gimme the link and I'll answer, be specific with details in the question.

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