I'm trying to show all the tables in my database. I've tried this:
$sql = "SHOW TABLES";
$result = $conn->query($sql);
$tables = $result->fetch_assoc();
foreach($tables as $tmp)
{
echo "$tmp <br>";
}
but it only gives me one table name in a database I know has 2. What am I doing wrong?
SHOW TABLESmysql> USE test;
Database changed
mysql> SHOW TABLES;
+----------------+
| Tables_in_test |
+----------------+
| t1 |
| t2 |
| t3 |
+----------------+
3 rows in set (0.00 sec)
SHOW TABLES IN db_namemysql> SHOW TABLES IN another_db;
+----------------------+
| Tables_in_another_db |
+----------------------+
| t3 |
| t4 |
| t5 |
+----------------------+
3 rows in set (0.00 sec)
mysql> SELECT TABLE_NAME
FROM information_schema.TABLES
WHERE TABLE_SCHEMA = 'another_db';
+------------+
| TABLE_NAME |
+------------+
| t3 |
| t4 |
| t5 |
+------------+
3 rows in set (0.02 sec)
you have fetched just 1 row. fix like this:
while ( $tables = $result->fetch_array())
{
echo $tmp[0]."<br>";
}
and I think, information_schema would be better than SHOW TABLES
SELECT TABLE_NAME
FROM information_schema.TABLES
WHERE TABLE_SCHEMA = 'your database name'
while ( $tables = $result->fetch_assoc())
{
echo $tables['TABLE_NAME']."<br>";
}
SHOW TABLE's output is something like 'Tables_in_TBL_NAME'. so when executed in client program. So column name is changed. and people don't know about information_schema which has more useful information about DB
information_schema.tables table gives me a lot more info. Always nice to look intoTry this:
SHOW TABLES FROM nameOfDatabase;
SHOW TABLE_NAME is not valid. Try SHOW TABLES
TD
SHOW TABLES only lists the non-TEMPORARY tables in a given database.
<?php
$dbname = 'mysql_dbname';
if (!mysql_connect('mysql_host', 'mysql_user', 'mysql_password')) {
echo 'Could not connect to mysql';
exit;
}
$sql = "SHOW TABLES FROM $dbname";
$result = mysql_query($sql);
if (!$result) {
echo "DB Error, could not list tables\n";
echo 'MySQL Error: ' . mysql_error();
exit;
}
while ($row = mysql_fetch_row($result)) {
echo "Table: {$row[0]}\n";
}
mysql_free_result($result);
?>
//Try This code is running perfectly !!!!!!!!!!
