I'm a newbie at using regex in c# and I'm trying to use it to validate a phone number with this format 09oxoxxxxxx where x can be any number and o can be only 1-9 and the total length should be 11 numbers. Here's what I think which is probably wrong.
if (Regex.IsMatch("09203041152", "^[0]{1}[9]{1}[1-9]{2}[1-9]{1}[0-9]{6}"))
You can use shorthand character \d which represents any number [0-9]:
Regex.IsMatch("09203041152", @"^09[1-9]\d[1-9]\d{6}$")
Your patter is not working due to repetitions count {2} here:
^[0]{1}[9]{1}[1-9]{2}[1-9]{1}[0-9]{6}
That requires two non-zero numbers in a row. But you need one non-zero number and one any number at this place:
^[0]{1}[9]{1}[1-9]{1}[0-9]{1}[1-9]{1}[0-9]{6}
Note - you don't need to specify repetitions count equal to {1}, because that means single token occurrence, which is true without specifying that explicitly.
The following RegExp should match the format you stated '09oxoxxxxxx'
^09[1-9][0-9][1-9][0-9]{6}$
Your regular expression is a bit more complex that it needs to be:
^09[1-9][0-9][1-9][0-9]{6}$
^: Match the start-of-line.09: Matches the number 0 followed by 0.[1-9]: Matches any number between 1 and 9.[0-9]: Matches any number between 0 and 9.[1-9]: Again matches any number between 1 and 9.[0-9]{6}: Matches any number between 0 and 9 six times.11.
Try this:
^09[1-9][0-9][1-9][0-9]{6}
