Loop through foreach array

Question

I'm having a problem looping through my array to get just one value each time. I want to gray only 1 value because I'm calling that value in jquery. I'm new and sorry if this is too basic but I've been trying for days, pulling my hair out!

$designslist = array('design1','design2','design3','design4');
$current_index = 0;
$current_id = current($designslist);
$next = $designslist[$current_index + 1];

foreach( $designslist as $value )
{
  if( $value !== $next )continue;
  $nexts =  $next;
  echo $nexts;
  $current_index++;
}

Inside my html

<a href="#" id="<?php echo $nexts; ?>">next</a>

calling the id with jquery

$('#design1').on('click',function() {
  $('#web1').removeClass().addClass('big1');
});

when asking a question, always make sure to indent your code and not mix tabs and spaces, because you want people to be able to read your code =) On a secondary note, don't use <a href="#"> anchors. This is a leftover from html 3.2, under html5 (and html 4.01) rules, this link will actually take you to the top of the page. — Mike 'Pomax' Kamermans
– Mike 'Pomax' Kamermans, Commented Nov 30, 2013 at 6:57
what is the output that you want?? can you please tell what you are trying to do with the loop??? — Let me see
– Let me see, Commented Nov 30, 2013 at 7:14
//My array Array ( [0] => design1 [1] => design2 [2] => design3 [3] => design4 ) I want the output design1 then next time i click the link design2 and so on — Dean Lark
– Dean Lark, Commented Nov 30, 2013 at 9:15
Well I've tried everything everyone has recomended but I still can't get it to do what I want. if anyone else has any suggestions please enlighten me. Thanks guys! — Dean Lark
– Dean Lark, Commented Nov 30, 2013 at 9:48

Onimusha · Accepted Answer · 2013-11-30 07:20:30Z

2

foreach( $designslist as $value )

needs to be

foreach( $designslist as $i => $value )

$i is the array index

answered Nov 30, 2013 at 7:20

Onimusha

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1 Comment

Dean Lark Over a year ago

//My array Array ( [0] => design1 [1] => design2 [2] => design3 [3] => design4 ) //set the current index? $current_id = current($designslist); //Next equals $next = $designslist[$i + 1]; $i = 0; foreach( $designslist as $i => $value ) if( $value !== $next )continue; $nexts = $next; echo $nexts; $i++; } what i need to do is loop through my array and get the design to be added into my <a href="" id="HERE"> which will keep looping each time I click the link. Thanks for all your help.

crafter · Accepted Answer · 2013-11-30 07:25:01Z

0

You can try array search

$tag       = array_search($value, $designslist);
$nexts     = $$designslist[$tag];

answered Nov 30, 2013 at 7:25

crafter

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Comments

Community · Accepted Answer · 2023-11-17 20:33:26Z

0

Ok, you seem to be mixing for with foreach using these "current_id" and "next" variables.

You can use this kind of foreach statement:

foreach ($designList as $key => $value) {
    echo "The key of $value is $key";
}

As you want to return only unique values, you should use the "array_unique" function. Try this:

foreach (array_unique($designList) as $key => $value) {
    echo "The key of $value is $key";
}

I know it's not related to the question, but, as you said you're new to this, there are some PHP tips you should follow.

You're mixing snake_case with camelCase in your variables. I recommend using camelCase, but it's up to you.

edited Nov 17, 2023 at 20:33

CommunityBot

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answered Nov 30, 2013 at 7:31

Eduardo Russo

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2 Comments

Dean Lark Over a year ago

//My array Array ( [0] => design1 [1] => design2 [2] => design3 [3] => design4 ) $current_id = current($designslist); $next = $designslist[$i + 1];--foreach( $designslist as $i => $value ){if( $value !== $next )continue; $nexts = $next; echo $nexts; $i++;} how do I echo out design1 then next time i click the link it should be design2 and so on

Eduardo Russo Over a year ago

You'll will need a variable in your JS to count the current "i", so you can get the next one. I think you should create a new question, focused in the JS / JQuery part!

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