Javascript Regex ##x##

Question

I'm trying to get a regex that pulls out the format from a string.

Take this example, "5x7 (+$50)" or "20x24 (+70)". Is there any easier way to pull out the ##x## or #x#?

Here's the current code example....As you'll see the substring doesn't necessarily work for all test cases.

var example = "5x7 ($50)";
var ex_arr = example.split("x");

console.log(ex_arr[0]);
console.log(ex_arr[1].substring(0, 2));

If there's always a space between them, just split again on space, and get the first value. — adeneo
– adeneo, Commented Dec 3, 2013 at 20:28

qJake · Accepted Answer · 2013-12-03 20:33:52Z

1

Try this:

^(\d+)x(\d+)\s.*$

Here's a fiddle demonstrating it: http://www.rexfiddle.net/RkUvHCK

Capture 1 is the first number, Capture 2 is the second number. Everything else is discarded.

answered Dec 3, 2013 at 20:33

qJake

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1 Comment

qJake Over a year ago

@NiettheDarkAbsol Indeed, it could be shortened to ^(\d+)x(\d+)\s or even ^(\d+)x(\d+) if it suits the asker's needs, but I like to be thorough. :)

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