Java Custom Exceptions

Question

I am trying to catch an exception, and then throw it.

try{
    arr = new class[arrLen]; //Goes to a constructor that may cause an exception
}
catch(Exception e){
    MyException e = new MyException;
    throw e;
}

As you can see, I am trying to execute a command, and then if it causes an exception, I want to create a new instance of MyException and then throw it.

What I am having problems with is whether I am supposed to create the "Exception e" and then try and create a new "MyException e", or am I supposed to make a new MyException, AKA

MyException f = new MyException;
throw f;

What's wrong with the syntax? I'm still pretty new to this community — bob
– bob, Commented Dec 4, 2013 at 0:08
Why do you want to catch and throw it? A catch and throw pattern makes not much sense in most cases but you can certainly do that. - "catch an exception, and then throw it" would be when you don't create a new one. You can also catch one exception then throw a different one. Or just catch it without throwing. Or not catch it at all and let other code handle it. — zapl
– zapl, Commented Dec 4, 2013 at 0:11
@bob your syntax is incorrect and won't compile. There are several problems, and you should make sure the code compiles before pasting it into a question. — Jim Garrison
– Jim Garrison, Commented Dec 4, 2013 at 0:14

disrvptor · Accepted Answer · 2013-12-04 00:04:45Z

1

You should create a new MyException with a new variable, like f. This new exception should use the original Exception as the cause. For example

MyException f = new MyException(e);
throw f;

Or you can reuse the e variable if MyException extends Exception.

e = new MyException(e);
throw e;

answered Dec 4, 2013 at 0:04

disrvptor

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1 Comment

bob Over a year ago

Awesome! Worked perfectly :D

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