Extract number from an URL regex java

Question

I need to extract an last number from an URL followed by a dash.

Example:

http://www.example.com/p-test-test1-a-12345.html

i need to extract the 12345 using regex.

i tried this -\d(.*?).html which gives me 2345 not sure why it removes 1 any idea?

Which technique are you using : grouping or Pattern and Matcher. — Nishant Lakhara
– Nishant Lakhara, Commented Dec 4, 2013 at 9:31

Tafari · Accepted Answer · 2013-12-04 08:57:25Z

4

It removes the first digit as you have invalid pattern it captures everything after -digit

-\d(.*?).html

-\d - matches a dash followed by a digit

(.*?) - captures any character (except new line) 0 or more times till next token is satisifed

. - matches any character (except new line)

html - matches html

Try this pattern:

PATTERN

(?<=-)\d+(?=\.html)

answered Dec 4, 2013 at 8:57

Tafari

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Comments

Michał Niklas · Accepted Answer · 2013-12-04 08:57:19Z

2

You must add \d to group: -(\d.*?).html

if it must be only digits then -(\d+)\.html is better.

answered Dec 4, 2013 at 8:57

Michał Niklas

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1 Comment

Tafari Over a year ago

it will match any numer followed by !html as well

Nishant Lakhara · Accepted Answer · 2013-12-04 09:36:19Z

1

Try This :

String pattern2 = ".*?(\\d+)\\.html";
System.out.println(s.replaceAll(pattern2, "$1"));

answered Dec 4, 2013 at 9:36

Nishant Lakhara

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Comments

BambooleanLogic · Accepted Answer · 2013-12-06 08:31:00Z

1

You're looking for a dash, then a digit, then capturing all characters before ".html", which is why the 1 was not captured.

Try this instead:

-(\d+)\.html

edited Dec 6, 2013 at 8:31

answered Dec 4, 2013 at 8:58

BambooleanLogic

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2 Comments

Toto Over a year ago

There're no needs to make the + ungreedy.

BambooleanLogic Over a year ago

@M42 You're quite right. I suppose that's what happens when I edit existing code without thinking it through properly.

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