Extract ip address and port from a string in javascript

Question

In my client side code, the user enter an address like:

http://192.168.1.52:8080/home/client.html

I would like to extract the ip address 192.168.1.52 and the port number 8080 separately.

Here is what I did to extract the ip, but failed!

var url = window.location.href;
ValidIpAddressRegex = new RegExp("^(25[0-5]|2[0-4]\\d|[0-1]?\\d?\\d)(\\.(25[0-5]|2[0-4]\\d|[0-1]?\\d?\\d)){3}$");

var ip= ValidIpAddressRegex.exec(url);
alert(ip);

What would be the correct way of extracting IP and port number in javascript.- Thank you

adeneo · Accepted Answer · 2013-12-07 00:00:36Z

6

The easiest would be to just use a fake anchor :

var str = 'http://192.168.1.52:8080/home/client.html'

var a = document.createElement('a')
a.href = str;
var host = a.hostname;
var post = a.port;

FIDDLE

If it's coming from the adressbar, this is already built in to document.location

answered Dec 7, 2013 at 0:00

adeneo

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Yuval Adam · Accepted Answer · 2013-12-06 23:59:37Z

5

window.location.hostname and window.location.port

Read more about window.location at https://developer.mozilla.org/en-US/docs/Web/API/window.location

answered Dec 6, 2013 at 23:59

Yuval Adam

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1 Comment

HaukurHaf Over a year ago

Yes, this is it. I didn't realize he was actually getting the value from the window.location :-)

HaukurHaf · Accepted Answer · 2013-12-07 00:00:09Z

3

This is a simple method to parse the information from a given URL-string (not necessarily from the actual document.location)

<script>
var url = 'http://192.168.1.52:8080/home/client.html';
var ip = url.split('/')[2].split(':')[0];
var port = url.split('/')[2].split(':')[1];
</script>

answered Dec 7, 2013 at 0:00

HaukurHaf

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Comments

Maksim Nesterenko · Accepted Answer · 2023-07-25 13:01:38Z

1

if the string is a valid URL you can use this

const url = new URL('http://192.168.1.52:8080/home/client.html');
console.log(url.hostname) // 192.168.1.52
console.log(url.port) // 8080

note that it'll throw in case the string is is not a valid URL

For the current page URL, as suggested before, use window.location object.

answered Jul 25, 2023 at 13:01

Maksim Nesterenko

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