Replace text using regex in RAD Studio

Question

I want to replace for example F(G(X,Y)); with H(X,Y); In RAD Studio IDE.

The regex I use is:

Find Expression: F$G\((.+)$\); Replace Expression: H($1)

The result is not as I expect:

Result: H($1)

It seems the RAD Studio does not recognize the $1 as the contents between two parentheses.
Anybody have an idea?
Thanks

Did you read the docs? They will tell you the correct syntax. — David Heffernan
– David Heffernan, Commented Dec 10, 2013 at 8:44
You didn't look hard enough. It's here: docwiki.embarcadero.com/RADStudio/en/Regular_Expressions From the IDE you can just press F1 in the replace dialog! Trying to guess regex syntax without reading the docs is pointless. — David Heffernan
– David Heffernan, Commented Dec 10, 2013 at 10:24
I have seen this link, as you see there is nothing about how to replace the group, Not $1 nor \1 will help. see my below comment. — mh taqia
– mh taqia, Commented Dec 10, 2013 at 10:29
No, it's right there in the link. You just have to read it all carefully. Braces group characters or expressions. Groups can be nested, with a maximum number of 10 groups in a single pattern. For the Replace operation, groups are referred to by a backslash and a number, according to the position in the "Text to find" expression, beginning with 0. For example, given the text to find and replacement strings, Find: {[0-9]}{[a-c]*}, Replace: NUM\1, the string 3abcabc is changed to NUMabcabc. — David Heffernan
– David Heffernan, Commented Dec 10, 2013 at 10:31

Keith Miller · Accepted Answer · 2013-12-10 14:05:22Z

17

Use {} to group the expression rather than () and \1 in the replacement text:

Find Expression: F$G\({.+}$\); Replace Expression: H(\0)

answered Dec 10, 2013 at 8:09

Keith Miller

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1 Comment

Thank you, the "H(\1)" should become "H(\0)" (Zero base)