I have a user_id array:
$user_id = Array ();
And I want to create different variable names for each object:
//Something like $this->user_0, $this->user_1, $this->user_2, ...
$i=0;
foreach ($this->user_id as $id){
$var = 'this->user'.$i;
$$var = new DatabaseObject_User($db);
$$var->loadForUser($db, $id);
$i++;
}
I want Something like $this->user_0, $this->user_1, $this->user_2, different variables for each Object.
Don't do this. You will have no end of troubles attempting to iterate and test these properties.
Simply use an array, eg
class Whatever {
private $user_id = []; // PHP 5.4 syntax, use array() if not applicable
private $users = [];
public function loadUsers() {
foreach ($this->user_id as $id){
$user = new DatabaseObject_User($db); // dunno where $db comes from
$user->loadForUser($db, $id);
$this->users[] = $user;
}
}
You can then access each user via an array index, eg
$this->users[n]; // where n is some integer; 0 <= n < count($this->users)
or iterate the array
foreach ($this->users as $user) {
/* @var $user DatabaseObject_User */
}
DatabaseObject_User class has a public user_id property, yes.Not sure why you would want them to be individual variables instead of just storing an array of users, but I think you're looking for this:
$i=0;
foreach ($this->user_id as $id){
$var = 'user'.$i;
$this->$var = new DatabaseObject_User($db);
$this->$var->loadForUser($db, $id);
$i++;
}
Keep in mind that it's generally a bad idea to dynamically declare class properties. It's not obvious that those properties exist and they're automatically made public. You might want to consider just using a $users class property.
