python 3 int() problems

Question

nextt[0:1] = "*2"

rds = int(nextt[0:1].replace("*",""))

And there is problem, it says:ValueError: invalid literal for int() with base 10: ''

I just need to delete "*" from string and convert it to int.

What type is nextt to allow for string slice assignment here? Or are you merely illustrating what you think nextt contains after slicing? — Martijn Pieters
– Martijn Pieters, Commented Dec 15, 2013 at 16:38

Martijn Pieters · Accepted Answer · 2013-12-15 16:37:28Z

4

You are slicing just one character:

>>> '*2foo'[0:1]
'*'

Replacing the * gives you an empty string. Perhaps you wanted to slice two characters?

>>> '*2foo'[:2]
'*2'

If you are slicing anyway, just pick the digit character without the *:

int(nextt[1])

answered Dec 15, 2013 at 16:37

Martijn Pieters

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Comments

Asterisk · Accepted Answer · 2013-12-15 16:42:34Z

1

 int('*2'.replace('*', ''))

answered Dec 15, 2013 at 16:42

Asterisk

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