print only certain positions in array in C

Question

I have been googling for a few days trying to find the correct syntax in C. to print an array in a set out of order arrangement. I am new to C but know php, Java well. Am I using the wrong logic approach?

What I would like to print out is

     "Here is your order, 2B 3C 1A"

I have tried using the following type of code but get,

     @[2] (null)[3] (null)[1]
     segmentation fault

     char *aa="1A";
     char *bb="2B";
     char *cc="3C";
     char * zz[]={aa,bb,cc};
     g_print("Here is your order, %s[2] %s[3] %s[1]",zz);

thanks Art

for(i=0;i<3;i++) printf("%s ", zz[i]);, change the order you like. — moeCake
– moeCake, Commented Dec 16, 2013 at 10:34

Some programmer dude · Accepted Answer · 2013-12-16 10:34:55Z

2

You have to print each string in the array:

g_print("Here is your order, %s %s %s",zz[1], zz[2], zz[0]);

Note the indexing!

If the number of items is set during runtime, you have to use a loop:

g_print("Here is your order,");
for (size_t i = 0; i < some_upper_limit; ++i)
    g_print(" %s", zz[i]);

Also note that you declare the aa, bb and cc variables wrong. You should either declare them as arrays, or as pointers to constant strings. That's because string literals are constant.

So:

char aa[]="1A";
char bb[]="2B";
char cc[]="3C";

or

const char *aa="1A";
const char *bb="2B";
const char *cc="3C";

answered Dec 16, 2013 at 10:34

Some programmer dude

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1 Comment

art vanderlay Over a year ago

thanks @Joachim Pileborg for the two alt's, now it makes sense. thx Art

thumbmunkeys · Accepted Answer · 2013-12-16 10:34:33Z

2

use:

 g_print("Here is your order, %s %s %s",zz[1], zz[2], zz[0]);

array indices start with 0. The contents of strings is not evaluated for the array indices.

answered Dec 16, 2013 at 10:34

thumbmunkeys

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