Concatenating arrays with numpy doesn't work

Question

time=3600000    
count=0
l=0
while l<=time:    

    d=[12,37,45,67,98,45,90]
    t=0
    while t<=time:
        Theta_t=d*t
        r=[]
        r.append(Theta_t)
        t+=360

    if count==0:
        Theta=np.array([r])
    else:
        np.concatenate((Theta,[r]),axis=0)
    count+=1
    l+=360

Now, my problem is it does not append values to Theta which should be a two dimensional array with every column contains the values of r. Such as, Theta=[[12,56,58,45],[56,87,54,56],[...],...].

Daniel S. · Accepted Answer · 2013-12-16 17:59:42Z

5

Next try:

Instead of

np.concatenate((Theta,[r]),axis=0)

do

Theta = np.concatenate((Theta,[r]),axis=0)

edited Dec 16, 2013 at 17:59

answered Dec 16, 2013 at 14:44

Daniel S.

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3 Comments

rahul_2008aust Over a year ago

I don't have the values of r before the loop. So, it will not work. If I will create an empty array with zero's for r, outside the loop and then append values, it will not also work for me.

rahul_2008aust Over a year ago

Here Theta should be a 2 dimensional array and output of theta should look like. Theta=[[12,56,58,45],[56,87,54,56],[...],...]

rahul_2008aust Over a year ago

Can I append instead of concatenate?

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