PyQt new dialog with parameter

Question

i've got issues trying to set up a new dialog from my main window passing a path argument, right now the dialog just flash and exit... I think the problem is where i show the windows but i can't figure out where i should put it!
In this XtractMainWindow.py file i set up the main window and get the path

from PyQt4.QtCore import *
from PyQt4.QtGui import *
import ui_XtractMainWindow
import AndroidDialog
import sys

class XtractMainWindow(QMainWindow, ui_XtractMainWindow.Ui_XtractMainWindow):
    def __init__(self, parent=None):
    super(XtractMainWindow, self).__init__(parent)
    self.setupUi(self)

    self.androidXtractButton.clicked.connect(self.setAndroid)

def setAndroid(self):
    filename = QFileDialog.getExistingDirectory(self, "Open Directory", "/home")
    print filename
    dialog = AndroidDialog.AndroidDialog(str(filename))
    dialog.show()


app = QApplication(sys.argv)
form =  XtractMainWindow()
form.show()
app.exec_()

This is the Dialog, in AndroidDialog.py file

from PyQt4.QtCore import *
from PyQt4.QtGui import *
import csv
import sys
import Android_extractor
import ui_android_dialog

class AndroidDialog(QDialog, ui_android_dialog.Ui_androidDialog):
    def __init__(self, filename, parent=None):
        super(AndroidDialog, self).__init__(parent)
        self.setupUi(self)

Thank you for any advice!

qurban · Accepted Answer · 2014-01-05 08:17:25Z

1

dialog = AndroidDialog.AndroidDialog(str(filename))
dialog.show()

Here you can see that you are saving the reference of dialog in a local variable. When setAndroid(self) is done with the execution, the dialog variable is collected (destroyed) by the garbage collector.

Please note that window exists as long as a reference to that window exists.

Do this:

self.dialog = AndroidDialog.AndroidDialog(str(filename))
self.dialog.show()

In this case self.dialog is a class member, that will not be collected or destroyed by the garbage collector.

edited Jan 5, 2014 at 8:17

answered Dec 19, 2013 at 16:36

qurban

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4 Comments

Rigel Over a year ago

You're right but the new dialog still don't show. I found that the metod to call is dialog.exec_() instead of show()

qurban Over a year ago

works fine here. The dialog does not disappear. You should accept the answer as it solves the problem, that may help someone in the future

Rigel Over a year ago

Not sure what was wrong before, but now it works. Thank you very much!

qurban Over a year ago

Please note that exec_() has a special purpose to use it, this method blocks the execution of the code at the point where exec_() is called, but show() returns the control immediately after showing the window.

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