Expected an indented block on an if statement [duplicate]

Question

# Check for log request
if len(sys.argv) >= 3:
    if sys.argv[3].lower() == 'log':
        logFiles = True

I haven't done Python for a while but I don't see anything wrong with the above code and it's saying that after the 'logFiles' before the = True is the problem.

Ideas?

if you are using vim ( which you should :) ), you may add set expandtab in .vimrc file and it will always insert space instead of tabs. — behzad.nouri
– behzad.nouri, Commented Dec 22, 2013 at 13:29

user2357112 · Accepted Answer · 2013-12-22 13:21:06Z

1

Python 2 treats a tab the same way Notepad does - as enough spaces to reach the next 8-space indentation level. This means if you mix tabs and spaces, you might see code that looks perfectly well indented, but Python sees a garbled mess. (In Python 3, Python will give you a helpful TabError: inconsistent use of tabs and spaces in indentation if it sees that you're mixing tabs and spaces.) Your code has a tab on the second line and 4 spaces and a tab on the second. This looks like 1 indent, then 2, but Python doesn't see it that way.

Don't mix tabs and spaces. If you can, use the -tt interpreter option to detect this, and use an editor with an option to display whitespace characters.

answered Dec 22, 2013 at 13:21

user2357112

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