Why result of the addition not captured in iteration?

Question

In the given code, why the result of the addition is not captured in iteration? Why x's value never changes?

public class Fortran {
    static int bump(int i) { return i + 2; }
    public static void main(String[] args) {
        for(int x = 0; x < 5; bump(x))
        System.out.print(x + " ");
    } 
}

Change the last line in your for statement to read x =bump(x). You're not capturing the result. — sircodesalot
– sircodesalot, Commented Dec 22, 2013 at 14:19

David Souther · Accepted Answer · 2013-12-22 14:21:19Z

3

Java passes values by copying, so bump only gets a copy of x
The value returned by bump is never assigned to x (perhaps you forgot x =).

Perhaps try

for(int x = 0; x < 5; x = bump(x))

edited Dec 22, 2013 at 14:21

David Souther

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answered Dec 22, 2013 at 14:19

fdreger

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Comments

Heaven42 · Accepted Answer · 2013-12-22 14:24:43Z

0

It's just cause your new value is never assigned. The correct way of doing that is more.

for(int x=0;x<5;x+=2)
{
    //do whatever you want
}

NB : x+=2 is a short writing for x=x+2

answered Dec 22, 2013 at 14:24

Heaven42

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