PHP Dynamic form( $_POST)

Question

so.. I'm facing a problem with dynamic form/$_POST... I need to echo the image i selected via radio button in the if(isset($_POST['Submit_bc3']))... But it's not working, I don't get it.. How can i make this problem go away? Code:

<?php
    $image_url = $user['image_location'];
    $directory2 = "../../../login_/assets/playercards/";
    $images2 = glob($directory2 . "*.jpg");
    if (isset($_POST['Submit_bc3'])) {
       echo $image2;
    }else{
       foreach($images2 as $image2)
    {
    echo '<img src="'.$image2.'" border="0" height="81px" width="156px" />';
    echo "<input type='Radio' name='".$image2."' value=''></input>";
    }
    }
?>



<button type="submit" class="button" name="Submit_bc3" data-bind="vortexExternalLinkAction: ''">_LETS_GO</button>

Your radio buttons don't make sense, each of them has a different name. All the buttons in a radio button group have to have the same name. The differences should be in the value. — Barmar
– Barmar, Commented Dec 24, 2013 at 11:09
You should give as @Barmar said, a unique name to every radio and in the value attribute you set the image name, so you can get it when you submit. — Jorge Campos
– Jorge Campos, Commented Dec 24, 2013 at 11:11
Aye, but I don't know how excatly to get away without radio button... — user3132286
– user3132286, Commented Dec 24, 2013 at 11:11

Barmar · Accepted Answer · 2013-12-24 11:14:22Z

1

You need to give all the buttons the same name so they'll be a single radio button group. Then you use that name in $_POST to get the value after submission.

if (isset($_POST['Submit_bc3'])) {
    echo $_POST['image2'];
}else{
    foreach($images2 as $image2)
        {
            echo '<img src="'.$image2.'" border="0" height="81px" width="156px" />';
            echo "<input type='Radio' name='image2' value='".htmlentities($image2)."'></input>";
        }
}

answered Dec 24, 2013 at 11:14

Barmar

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Comments

CRABOLO · Accepted Answer · 2014-12-12 08:16:25Z

1

$image2 doesn't exist in the code before you echo it after checking whether the variable in POST isset.

edited Dec 12, 2014 at 8:16

CRABOLO

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answered Dec 24, 2013 at 11:13

Obversity

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1 Comment

user3132286 Over a year ago

Do you have any idea how could I change it? A little snippet?

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