Given a fixed length list and a function
l = [1, 2, 3, 4, 5]
def printMiddle(first, middle, last):
print middle
printMiddle(*l)
How do I force middle to print l[1:3] with the output below?
[2, 3, 4]
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what u r passing to printMiddle function??Vb407– Vb4072013-12-24 17:06:48 +00:00Commented Dec 24, 2013 at 17:06
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What is the expected output? Please give examples of input-output.Christian Tapia– Christian Tapia2013-12-24 17:07:02 +00:00Commented Dec 24, 2013 at 17:07
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Added finction call and output inlineEric Fossum– Eric Fossum2013-12-24 17:09:37 +00:00Commented Dec 24, 2013 at 17:09
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Be more clear on your Question...Siva Cn– Siva Cn2013-12-24 17:16:10 +00:00Commented Dec 24, 2013 at 17:16
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2 Answers
You could do:
l = [1, 2, 3, 4, 5]
def printMiddle(*args):
print(args[1:-1])
printMiddle(*l)
The asterisk * makes args a tuple of the positional arguments (parameters, as you have it) to the function. [1:-1] takes a slice of all but the first and last items in the tuple.
Comments
Try this:
l = [1, 2, 3, 4, 5]
def printMiddle(lst,first, last):
print lst[first:last]
printMiddle(l,1,4)
Although It would be much sensible to do like this:
l = [1, 2, 3, 4, 5]
print l[1:4]
