How to check if array has required keys in PHP?

Question

I know PHP has a lot of functions for arrays, but I am not sure which one to use know, or if custom function is needed.

I have a function that accepts arrays, and I would need those arrays passed as arguments to have certain keys. When an array is passed, I would need to check if the form of the arrays is proper, example:

<?php function( $array ) {
      // Array needs to have form Array('server'=>, 'database'=>,'username'=>
      I could check it as "array_key_exists", but it seems too long, there must be a
     a way to iterate throught arguments
     $template = Array('server'=>'', 'database'=>'','username'=>'');

     foreach( $array AS $key => $value ) {
       //Somehow compare if array $array includes keys as $template

Is there any way to do this? Thank you very much.

Array_intersect_key might be useful here.

mario
– mario

2013-12-29 21:16:23 +00:00
Commented Dec 29, 2013 at 21:16 — mario
– mario, Commented Dec 29, 2013 at 21:16
Thank you, very simple solution.

user3104270
– user3104270

2013-12-29 21:17:49 +00:00
Commented Dec 29, 2013 at 21:17 — user3104270
– user3104270, Commented Dec 29, 2013 at 21:17

ComFreek · Accepted Answer · 2013-12-29 21:31:52Z

3

array_intersect_key() as mario mentioned

$template = array('server', 'database', 'username');
if (array_intersect_key($template, array_keys($array)) == $template) {
  // all parameters were passed
}

array_diff():

$template = array('server', 'database', 'username');
if (empty(array_diff($template, array_keys($array)))) { 
  // all parameters got passed
}

For PHP < 5.5.0: replace the IF construct with count(array_diff($template, $array)) == 0

edited Dec 29, 2013 at 21:31

answered Dec 29, 2013 at 21:17

ComFreek

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2 Comments

Amal Over a year ago

+1. Just realized my answer and the second part of your answer is almost identical. :)

ComFreek Over a year ago

@AmalMurali I've fixed a bug in both code samples thanks to your answer! I was missing the array_keys parts.

moonwave99 · Accepted Answer · 2013-12-29 21:18:46Z

0

if(array_intersect( array_keys($array), array_keys($template)) == array_keys($template)){
  // do your business
}

answered Dec 29, 2013 at 21:18

moonwave99

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Comments

Amal · Accepted Answer · 2013-12-29 21:24:42Z

0

Use array_diff() and array_keys()

function check_keys(array $array) {
    $template = array('server', 'database', 'username');
    return (count(array_diff($template, array_keys($array))) == 0);
}

answered Dec 29, 2013 at 21:24

Amal

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