280

How can I have a view render a partial (user control) from a different folder? With preview 3 I used to call RenderUserControl with the complete path, but whith upgrading to preview 5 this is not possible anymore. Instead we got the RenderPartial method, but it's not offering me the functionality I'm looking for.

10 Answers 10

488

Just include the path to the view, with the file extension.

Razor:

@Html.Partial("~/Views/AnotherFolder/Messages.cshtml", ViewData.Model.Successes)

ASP.NET engine:

<% Html.RenderPartial("~/Views/AnotherFolder/Messages.ascx", ViewData.Model.Successes); %>

If that isn't your issue, could you please include your code that used to work with the RenderUserControl?

Sign up to request clarification or add additional context in comments.

5 Comments

I wish we could just say /AnotherFolder/Messages
@Simon_Weaver You can achieve that. One way would be to modify ViewEngine and override it's FindPartialView method with something like if(partialViewName.Contains"/")partialViewName="~/Views/"+partialViewName;
Works in the MVC 3 Razor engine as well, but like the above, you need the extension (.cshtml).
If its under different are you would need to give path "~/Areas/TestArea/Views/Shared/_SomePartial.mobile.cshtml"
How do you handle different cultures of that partial view (for example ~/Views/AnotherFolder/Messages.en.cshtml)?
38

In my case I was using MvcMailer (https://github.com/smsohan/MvcMailer) and wanted to access a partial view from another folder, that wasn't in "Shared." The above solutions didn't work, but using a relative path did.

@Html.Partial("../MyViewFolder/Partials/_PartialView", Model.MyObject)

2 Comments

Similarly @Html.Partial("../Shared/_PartialView") to use the Shared folder.
I'm finding that this doesn't work without the .cshtml extension at the end.
30

If you are using this other path a lot of the time you can fix this permanently without having to specify the path all of the time. By default, it is checking for partial views in the View folder and in the Shared folder. But say you want to add one.

Add a class to your Models folder:

public class NewViewEngine : RazorViewEngine {

   private static readonly string[] NEW_PARTIAL_VIEW_FORMATS = new[] {
      "~/Views/Foo/{0}.cshtml",
      "~/Views/Shared/Bar/{0}.cshtml"
   };

   public NewViewEngine() {
      // Keep existing locations in sync
      base.PartialViewLocationFormats = base.PartialViewLocationFormats.Union(NEW_PARTIAL_VIEW_FORMATS).ToArray();
   }
}

Then in your Global.asax.cs file, add the following line:

ViewEngines.Engines.Add(new NewViewEngine());

2 Comments

Of course I realize this question was asked a long time ago. Thought I'd add to it for future Googlers and future Bingers.
- Won't work in .Net Core 2.2, as RazorViewEngine.PartialViewLocationFormats doesn't exist.
12

For readers using ASP.NET Core 2.1 or later and wanting to use Partial Tag Helper syntax, try this:

<partial name="~/Views/Folder/_PartialName.cshtml" />

The tilde (~) is optional.

The information at https://learn.microsoft.com/en-us/aspnet/core/mvc/views/partial?view=aspnetcore-3.1#partial-tag-helper is helpful too.

Comments

7

For a user control named myPartial.ascx located at Views/Account folder write like this:

<%Html.RenderPartial("~/Views/Account/myPartial.ascx");%>

Comments

5

I've created a workaround that seems to be working pretty well. I found the need to switch to the context of a different controller for action name lookup, view lookup, etc. To implement this, I created a new extension method for HtmlHelper:

public static IDisposable ControllerContextRegion(
    this HtmlHelper html, 
    string controllerName)
{
    return new ControllerContextRegion(html.ViewContext.RouteData, controllerName);
}

ControllerContextRegion is defined as:

internal class ControllerContextRegion : IDisposable
{
    private readonly RouteData routeData;
    private readonly string previousControllerName;

    public ControllerContextRegion(RouteData routeData, string controllerName)
    {
        this.routeData = routeData;
        this.previousControllerName = routeData.GetRequiredString("controller");
        this.SetControllerName(controllerName);
    }

    public void Dispose()
    {
        this.SetControllerName(this.previousControllerName);
    }

    private void SetControllerName(string controllerName)
    {
        this.routeData.Values["controller"] = controllerName;
    }
}

The way this is used within a view is as follows:

@using (Html.ControllerContextRegion("Foo")) {
    // Html.Action, Html.Partial, etc. now looks things up as though
    // FooController was our controller.
}

There may be unwanted side effects for this if your code requires the controller route component to not change, but in our code so far, there doesn't seem to be any negatives to this approach.

Comments

4

The VirtualPathProviderViewEngine, on which the WebFormsViewEngine is based, is supposed to support the "~" and "/" characters at the front of the path so your examples above should work.

I noticed your examples use the path "~/Account/myPartial.ascx", but you mentioned that your user control is in the Views/Account folder. Have you tried

<%Html.RenderPartial("~/Views/Account/myPartial.ascx");%>

or is that just a typo in your question?

Comments

0

you should try this

~/Views/Shared/parts/UMFview.ascx

place the ~/Views/ before your code

Comments

0

Create a Custom View Engine and have a method that returns a ViewEngineResult In this example you just overwrite the _options.ViewLocationFormats and add your folder directory :

public ViewEngineResult FindView(ActionContext context, string viewName, bool isMainPage)
        {
            var controllerName = context.GetNormalizedRouteValue(CONTROLLER_KEY);
            var areaName = context.GetNormalizedRouteValue(AREA_KEY);

            var checkedLocations = new List<string>();
            foreach (var location in _options.ViewLocationFormats)
            {
                var view = string.Format(location, viewName, controllerName);
                if (File.Exists(view))
                {
                    return ViewEngineResult.Found("Default", new View(view, _ViewRendering));
                }
                checkedLocations.Add(view);
            }

            return ViewEngineResult.NotFound(viewName, checkedLocations);
        }

Example: https://github.com/AspNetMonsters/pugzor

Comments

-4

Try using RenderAction("myPartial","Account");

1 Comment

Please Read the question as the user is asking about view in different folder where is folder in your code ?

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.