How to alert a php array in ajax success function

Question

I know that this question is so simple to ask, but I wasn't able to find the right answer for it, by going through many questions on stack overflow or by googling. So I found noway but to place the question here.

I have a mysql table as follow:

 [0]1>>>>2>>>>>3>>>>>5>>>>>6
 [1]1>>>>2>>>>>3>>>>>5>>>>>6
 [2]1>>>>2>>>>>3>>>>>5>>>>>6
 [3]1>>>>2>>>>>3>>>>>5>>>>>6
 [4]1>>>>2>>>>>3>>>>>5>>>>>6
 [5]1>>>>2>>>>>3>>>>>5>>>>>6

I need to store it in a variable and parse it with json back to the ajax function, but the result I get is [object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],

Here is the php code:

 $ent = $_POST['id'];
 $column = array();
 $gtord = mysql_query("SELECT * FROM order WHERE oId = '$ent' ");
 while($rowmnu2=mysql_fetch_assoc($gtord))           
{
   $column[]  = array($rowmnu2);
}
  echo json_encode($column);

here is the ajax function:

 $.ajax({
  type: 'POST',
  url: "profile/ajax/getorder.php",
  data: {id:gotid},
  dataType: 'json',
  cache: false,
  success: function(result) {
          alert(result);
     },
   });

I am sure that there is an error in my ajax code success alert, but I am not able to figure it out, how to go through the received array.

Please help me. Appreciated in advance.

@Nouphal.M, I did try that too, the php file itself will echo the whole array correctly, but the ajax still alerts object :( — Kissa Mia
– Kissa Mia, Commented Jan 1, 2014 at 6:42
If you want to go through the received array, write a for loop. alert() doesn't show the contents of objects, use console.log() to see the data. — Barmar
– Barmar, Commented Jan 1, 2014 at 6:42
@Barmar, ok I'll need to search about how to use console.log then :(, but is that the only way ??? — Kissa Mia
– Kissa Mia, Commented Jan 1, 2014 at 6:48

Barmar · Accepted Answer · 2014-01-01 06:50:12Z

1

Try:

alert(JSON.stringify(result));

answered Jan 1, 2014 at 6:50

Barmar

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