Javascript get context of function

Question

There is some JavaScript I want to debug (e.g. make something which was written for Ext JS 4 work with Ext JS 3). And there is function define, which is absent in version 3. I wanted just paste it's code, but don't know where it lies. I printed it:

>>> Ext.define.toString()
"function (i, j, h) { if (j.override) { return a.createOverride.apply(a, arguments); } return a.create.apply(a, arguments); }"

But still, I don't know what is a. How could I, having function object get the source for context of that object?

It's JavaScript: you can just read the source code, can't you? — freakish
– freakish, Commented Jan 3, 2014 at 12:06
You could also try to use Ext.define and then step into it using debugger. — nooga
– nooga, Commented Jan 3, 2014 at 12:10

Juan Sánchez · Accepted Answer · 2014-01-03 12:10:33Z

1

You may update your ExtJS 3 to latest version. In ExtJS 3.4.1.1, which is the latest version of ExtJS you can download from Sencha website here.

As it was introduced in ExtJS 3.4.0 (once ExtJS 4 was out), the behaviour must be near the same, so maybe you will require less changes in the code to make it work with ExtJS 3

answered Jan 3, 2014 at 12:10

Juan Sánchez

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nooga · Accepted Answer · 2014-01-03 12:15:07Z

1

Extracted from: https://extjs-public.googlecode.com/svn/extjs-4.x/include/ext-dev.js

define: function (className, data, createdFn) {
        Ext.classSystemMonitor && Ext.classSystemMonitor(className, 'ClassManager#define', arguments);

        if (data.override) {
            return Manager.createOverride.apply(Manager, arguments);
        }

        return Manager.create.apply(Manager, arguments);
    },

Apparently, your a is Manager. I doubt if this helps to move define to Ext 3 but here you go :)

answered Jan 3, 2014 at 12:15

nooga

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