Get current page URL without query parameters - Razor Html helper?

Question

Is there a method in Razor that returns the current pages URL without the query parameters.

I need to shove it into an HTML helper method I have created as a string.

@Url does not seem to work and if I do .ToString() I just get the namespace LOLLL

Razor use:

<th width="100%" @Html.SortTableClickEvent(@Url.ToString(), "Name")>

Html helper:

    public static MvcHtmlString SortTableClickEvent(this HtmlHelper html, string url, string column)
    {
        StringBuilder sortingPropertiesObject = new StringBuilder();
        sortingPropertiesObject.Append("var properties = new James.prototype.Table.SortingProperties();");
        sortingPropertiesObject.Append("properties.url = \"" + url + "\"");
        sortingPropertiesObject.Append("properties.colName = \"" + column + "\"");

        string clickEvent = "onclick = James.Table.SortByColumn(properties, this);";

        return MvcHtmlString.Create(sortingPropertiesObject + clickEvent);
    }

What gets output to my html:

<th width="100%" onclick='James.Table.SortByColumn("Name",' this);="" properties.colname="Name" james.prototype.table.sortingproperties();properties.url="System.Web.Mvc.UrlHelper" properties="new" var="">
            Name
        </th>

Andrei · Accepted Answer · 2014-01-06 11:31:55Z

30

You can use Request.Url.GetLeftPart method for that. If your URL is say

http://the-site.com/controller/action?param=1

executing Request.Url.GetLeftPart(UriPartial.Path) should give

http://the-site.com/controller/action

In code that might look like this:

<th width="100%" @Html.SortTableClickEvent(@Request.Url.GetLeftPart(UriPartial.Path), "Name")>

answered Jan 6, 2014 at 11:31

Andrei

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2 Comments

Jimmyt1988 Over a year ago

@Request.Path seems to do the job too!

Andrei Over a year ago

@JamesT, well, it depends on what your needs. If you need full path, with scheme and domain parts, then GetLeftPart is to be used. If /controller/action part is enough for you - then Request.Path will do indeed.

Giorgio Minardi · Accepted Answer · 2014-01-06 11:32:06Z

9

Without querystring:

Request.Url.GetLeftPart(UriPartial.Path)

With querystring

Request.Url.PathAndQuery

answered Jan 6, 2014 at 11:32

Giorgio Minardi

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Comments

DeadlyChambers · Accepted Answer · 2015-02-19 20:09:30Z

2

This is what I used which also works to get rid of ANYTHING the right of the action.

 public static string GetParameterlessPath(ActionExecutingContext filterContext)
    {
        return GetParameterlessPath(filterContext.ActionDescriptor.ActionName,
            VirtualPathUtility.ToAppRelative(filterContext.HttpContext.Request.Path));
    }

    public static string GetParameterlessPath(string action, string relativeUrl)
    {
        return  relativeUrl.Contains(action) 
             ? relativeUrl.Substring(0, relativeUrl.LastIndexOf(action))+action 
             : relativeUrl;
    }

This is obviously a static method, but I put it in my ActionFilter hence where I am getting the ActionExecutingContext. If you have the action and the relativeUrl (or any url for that matter) that bottom method should work for you.

edited Feb 19, 2015 at 20:09

answered Feb 19, 2015 at 18:35

DeadlyChambers

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1 Comment

Donnelle Over a year ago

And a version for JS: function GetParameterlessPath(action, relativeUrl) { if (relativeUrl.indexOf(action) == -1) return relativeUrl; return relativeUrl.substring(0, relativeUrl.lastIndexOf(action)) + action; }

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