Finding the mode of an array: no output

Question

I'm writing a program that takes 10 numbers as input and displays the mode of the numbers using parallel arrays and a method that takes an array of numbers as a parameter and returns the value that appears most often in the array. PROBLEM: However, when I run my program it has absolutely no output, also, I am not sure how to implement the parallel arrays. Does anyone know? Thank you.

import java.util.Scanner;

public class Mode {

public static void main(String[] args) {
}

public int computeMode(int[] nums) {
    Scanner scanner = new Scanner(System.in);

    int maxValue = -1;
    int maxCount = 0;
    int x = 0;
    //count how many times nums[i] appears in array

    System.out.println("Enter 10 numbers: ");
    for (int i = 0; i < 10; i++) {

        try { //try catch exception to catch decimal inputs as well as more /less than 10 integers
            x = scanner.nextInt();
        } catch (Exception e) {
            System.out.println("Invalid input! Please reenter 10 integer values.");
            scanner = new Scanner(System.in);
            i = -1;

            continue;
        }
        for (i = 0; i < nums.length; i++) {
            int count = 0;
            for (int j = 0; j < nums.length; j++) {
                if (nums[j] == nums[i]) {
                    count++;
                }
            }

            if (count > maxCount) {
                maxValue = nums[i];
                maxCount = count;
                System.out.println("The mode is: " + maxValue);
            }

        }

    }
    return maxValue;
}

}

score 2 · Accepted Answer · 2014-01-10 02:16:05Z

2

The main function is empty, so it does not anything, and the function doesn't need any parameter, because you read the numbers with the scanner

I think you need this:

import java.util.Scanner;

class Mode {
    public static void main(String[] args) {
        computeMode();
    }

    public static void computeMode(){
        int nums[]=new int[10];
        Scanner scanner = new Scanner(System.in);

        int maxValue = -1;
        int maxCount = 0;
        int x = 0;
        //count how many times nums[i] appears in array

        System.out.println("Enter 10 numbers: ");
        for (int i = 0; i < 10; i++) {

            try { //try catch exception to catch decimal inputs as well as more /less than 10 integers
                x = scanner.nextInt();
                nums[i]=x;
            } 
            catch (Exception e) {
                System.out.println("Invalid input! Please reenter 10 integer values.");
                i =i -1;
                scanner.nextLine();

                continue;
            }
        }
        for (int i = 0; i < nums.length; i++) {
            int count = 0;
            for (int j = 0; j < nums.length; j++) {
                if (nums[j] == nums[i]) {
                    count++;
                }
            }

            if (count > maxCount) {
                maxValue = nums[i];
                maxCount = count;

            }

        }
    System.out.println("The mode is: " + maxValue);
    }


}

edited Jan 10, 2014 at 2:16

answered Jan 10, 2014 at 2:06

user2154826

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2 Comments

user3053348 Over a year ago

Aha this works, thank you. Do you happen to know if this method uses parallel arrays? And how I would edit the exception to catch only letters or symbols (anything that is not a number as the program simply specifies number...which I assume means either an integer or a decimal). @TurtleLoop

user2154826 Over a year ago

There is only one array (nums[]), then this method doesn't use parallel arrays. Here you have an example of parallel arrays: mathbits.com/MathBits/Java/arrays/ParallelArrays.htm

Chris Culter · Accepted Answer · 2014-01-10 02:06:03Z

0

The code writes x, but never reads it; reads nums, but never writes it; and implements computeMode, but never calls it.

answered Jan 10, 2014 at 2:06

Chris Culter

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