How do I fix an arrayindexoutofboundsexception error?

Question

this is the code I am dealing with

public class NameTag
{
    public static void main (String[] args)
    {
        System.out.println ();
        System.out.println ("   " + args[0]);
        System.out.println ("My name is " + args[1]);
        System.out.println ();
    }
}

this is the error that keeps showing each time I try to run the program java.lang.ArrayIndexOutOfBoundsException: 0 at NameTag.main(NameTag.java:6)

I am using BlueJ Version 3.1.0 *I have no idea how to fix this error, I have tried many different things but nothing is working. Please help.*

You need to pass some arguments (at least 2 with your code) when running your main method. — Alexis C.
– Alexis C., Commented Jan 16, 2014 at 18:53
are you aware what the purpose of the args array is and are you doing what needs to be done to fill it when you run the program? — Philipp
– Philipp, Commented Jan 16, 2014 at 18:53
You need to run the program with at least two arguments on the command line. I'm not familiar with BlueJ so I don't know how to run programs and pass arguments. — ajb
– ajb, Commented Jan 16, 2014 at 18:54

Martin Dinov · Accepted Answer · 2014-01-16 18:53:37Z

2

That means you haven't passed any arguments to the program at execution. Therefore, accessing args[0] and args[1] leads to the ArrayIndexOutOfBoundsException. http://www.bluej.org/help/archive.html#tip9 explains how to pass command line arguments to BlueJ. To save you the trouble of following the link, pass the following parameter to main:

{ "foo", "bar" }

to have the String "foo" in args[0] and "bar" in args[1]. Also, it's good practice to check the length of the args array before doing anything with it, to make sure that arguments have indeed been passed.

answered Jan 16, 2014 at 18:53

Martin Dinov

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Neeraj Krishna · Accepted Answer · 2014-01-16 18:56:24Z

1

Check for the length of the array before doing any other operations.

public static void main (String[] args)
{
    if(args.length > 1) {
       System.out.println ();
       System.out.println ("   " + args[0]);
       System.out.println ("My name is " + args[1]);
       System.out.println ();
    }
}

answered Jan 16, 2014 at 18:56

Neeraj Krishna

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user2685079 · Accepted Answer · 2014-01-16 18:56:22Z

0

On blueJ, when you run, make sure you enter your input in the correct way and not empty. It will take your input and evaluate args[0] and args[1] from the input. It throws the exception when it can't find any argument.

answered Jan 16, 2014 at 18:56

user2685079

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