how can I append a multi-line variable to an array

Question

I have a multi-line variable in a bash script (contains output from a command that is executed automatically via SSH). How can I append this variable to an array so that each line in the variable is put into a new row/member of the array?

something="first row
           second row
           third row"

echo "${something_array[0]}" - first row
echo "${something_array[1]}" - second row
echo "${something_array[2]}" - third row

There "could" already be data inside the array, therefore I am try to append the lines to the array. I have already tried

IFS='\n' something_array=($(echo -e "$something"))

although I ran into some issues, plus it does not append the data either

devnull · Accepted Answer · 2014-01-17 13:35:44Z

2

You wanted to use ANSI-C Quoting for defining IFS. Say:

IFS=$'\n' something_array=($(echo -e "$something"))

instead.

In order to append to the array, say:

IFS=$'\n' something_array+=($(echo -e "$something"))

edited Jan 17, 2014 at 13:35

answered Jan 17, 2014 at 13:02

devnull

124k33 gold badges247 silver badges234 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

lacrosse1991 Over a year ago

Thanks! would you know how to append data with that by any chance? I tried += after the variable but it resulted in all data being placed in the first row of the array [0]

devnull Over a year ago

@lacrosse1991 No, saying IFS=$'\n' something_array+=($(echo -e "$something")) should append.

Collectives™ on Stack Overflow

how can I append a multi-line variable to an array

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related