XML parsing error

Question

I am getting org.xml.sax.SAXParseException: An invalid XML character (Unicode: 0x12) was found in the element content of the document. error on the client side. Can someone tell what is the regular expression using java.util.regex.Pattern to replace such characters so that I can exclude in the server side.

tried..

Pattern PATTERN = Pattern.compile("\0012");

but didn't work

possible duplicate: stackoverflow.com/questions/10148145/… — pisek
– pisek, Commented Jan 22, 2014 at 16:18

keshlam · Accepted Answer · 2014-01-22 16:20:15Z

1

Most "control characters" (<32 ASCII) are not legal in XML 1.0. Some of them are legal in XML 1.1. If your users expect them to be supported, you may want to make sure you're using a parser which can handle the newer Recommendation.

answered Jan 22, 2014 at 16:20

keshlam

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Ed Staub · Accepted Answer · 2014-01-22 16:26:52Z

0

When you need to look for some literal string with stuff in it that the regex parser is likely to have trouble with, use Pattern.quote() around the literal.

Also, you're using an octal encoding, not a unicode one - you forgot the u after \.

In this case:

Pattern PATTERN = Pattern.compile(Pattern.quote("\u0012"));

Note: I haven't tried this particular case!

answered Jan 22, 2014 at 16:26

Ed Staub

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1 Comment

Ed Staub Over a year ago

@java1977 I thought it probably would, but I so often forget about regex specifics that I reach for quote() whenever there's any question. It's faster to write than to read everything, and unlike me, never makes mistakes.

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