Writing script to find all PID of processes of user

Question

I really want to use ps -aux to get this. So I wrote script:

#!/bin/bash
if [ $# -lt 1 ]; then
        echo -n "No arguments were written"
        read uid
else
        uid=$1
fi
procesy=`ps -aux | awk '{if ($1=="$uid") print$2}'`
echo $procesy

Why it is not working ? When I am writinig ./script root I am getting nothing but blank line.

Check your man page. ps should already have an option to output just the process IDs, without having to filter them out of the full output of ps -aux. — chepner
– chepner, Commented Jan 23, 2014 at 13:30
For the people who wants to close the question, the question isn't about how to use awk if you have a solution that doesn't use awk feel free to add. — Loïc Faure-Lacroix
– Loïc Faure-Lacroix, Commented Jan 23, 2014 at 21:39
@devnull are you saying that this answer could be answered only using awk? — Loïc Faure-Lacroix
– Loïc Faure-Lacroix, Commented Jan 23, 2014 at 21:59

l0b0 · Accepted Answer · 2014-01-23 12:38:44Z

4

This will do what you need:

pgrep -U $1

answered Jan 23, 2014 at 12:38

l0b0

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Comments

Radu Rădeanu · Accepted Answer · 2014-01-23 12:47:07Z

1

In your script you have a problem using a shell variable inside awk. The right way using awk should be something like:

#!/bin/bash
if [ $# -lt 1 ]; then
        echo -n "No arguments were written"
        read user
else
        user=$1
fi
procesy=`ps aux | awk -v usr=$user '{if ($1==usr) print$2}'`
echo $procesy

answered Jan 23, 2014 at 12:47

Radu Rădeanu

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1 Comment

Radu Rădeanu Over a year ago

@LoïcFaure-Lacroix Because this was about in the question.But I am aware that l0b0's solution is better.

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