Similar to here: Does Python have a string contains substring method? This question only deals with one substring within a string, I want to test one of several.
Something like:
if 'AA' or 'BB' or 'CC' not in string:
print 'Nope'
However, if my test string is:
string='blahblahAA'
the if still evaluates to True and prints the statement. I'm probably just understanding the syntax incorrectly, any help would be appreciated.
Thanks!
Use any for this:
>>> s = 'blahblahAA'
>>> any(x not in s for x in ('AA', 'BB', 'CC'))
True
Your current code is equivalent to:
if ('AA') or ('BB') or ('CC' not in string)
As 'AA' is True(bool('AA') is True), so this always evaluates to True.
not all(x in s for x in ('AA', 'BB', 'CC')) might be more readable hereTrue if any of the string is not in s. :)(!A || !B) == !(A && B) looks at the code and goes "huh"? (While I would hope that most programmers are aware of that property of Boolean algebra, there's always the possibility of one that doesn't.) I do prefer Ashwini's version, personally, but that's just a matter of taste; if the question were asking for none of the substrings to be present, I'd probably use not any(x in s for x in ('AA', 'BB', 'CC')), though all(x not in s for x in ('AA', 'BB', 'CC')) would work as well.
You should use an and instead of an or statement. Right now, you always print 'Nope' if one of the substrings is not in your string.
In the example given above, you still print 'Nope' because 'BB' and 'CC' are not in the string and the whole expression evaluates to true.
Your code could look like this:
if ('AA' not in string) and ('BB' not in string) and ('CC' not in string):
print 'Nope'
