PHP Method Check if used for assignment

Question

I am not sure if this is possible, however, can we build a method that returns or echo the result based on calling the method directly or used in assignment

function foo()
{
    return "bar";
}

$abc = foo();
// $abc will have the value "bar"

But if foo() is called directly, it should echo "bar"

foo();
// should echo / print "bar"

adding echo before foo() solves the problem, but how could this be achieved without using echo. Probably adding some line of code to the function foo()

Method itself has no idea how it will be used in outer scope (it may be in expression, in single call, in assignment or even in some thing like eval() ) — Alma Do
– Alma Do, Commented Jan 29, 2014 at 6:50
@AlmaDo, thanks! however, there should be something i can manage the default method behaviour based on how it is called — Guns
– Guns, Commented Jan 29, 2014 at 6:52
You can pass some parameter to function for decide functionality — user2801382
– user2801382, Commented Jan 29, 2014 at 6:56
Ok. Good luck with $x = function() { return call_user_func(chr(102).str_repeat('o', 2)); }; eval('echo $x();'); — Alma Do
– Alma Do, Commented Jan 29, 2014 at 6:58

user2801382 · Accepted Answer · 2014-01-29 06:55:14Z

1

There is a possible way is to echo inside your function . Just like

<?php function foo()
{
    echo "bar";
    return "bar";
}

 echo $abc = foo();
?>

answered Jan 29, 2014 at 6:55

user2801382

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1 Comment

Guns Over a year ago

this would not work. if we use $abc = foo(); to get value into $abc, it would echo the value as well.

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