Converting Newlines in JSON array to line breaks: JSON_decode and nl2br

Question

I cannot get the below array to replace the carriage return and newline with an HTML break  

JSON Array:

{"Fruit":"Apple","Veggies":"Carrot\r\nCelery\r\n\r\nCucumbers"}

I'm trying this and having no luck:

$html = json_decode(nl2br($json),true);

The line breaks are visible in the source code of the HTML itself however I cannot get the   code to replace the 'newlines'.

I've tried this suggestion as well and it did not work either: Replacing \r\n (newline characters) after running json_encode

how did you get the json? I think is better replace before make the json encode or after if you dont have the possibility of edit the json — Emilio Gort
– Emilio Gort, Commented Jan 31, 2014 at 4:33

dabra904 · Accepted Answer · 2014-01-31 04:41:02Z

2

Run nl2br() after JSON is decoded, not on the JSON array source.

answered Jan 31, 2014 at 4:41

dabra904

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user2672373 · Accepted Answer · 2014-01-31 04:40:37Z

0

Perhaps you should try

$arJson = array( 'fruit' => 'apple', 
                 'veggies' => array( 'carrot', 'celery', 'cucumbers' ) );

header( 'Content-Type: application/json' );

print json_encode( $arJson );

Which returns a JSON

Then use jQuery or your favorite library( even a custom build one ) to send an ajax request to the page.

$.ajax({

    url: 'frtsnvgs.php',
    dataType: 'JSON',
    success: function( oData ) {
        $.each( oData, function( key, value ) {
            document.write( key + ': ' + value + '<br>' );
        });
    }

});

answered Jan 31, 2014 at 4:40

user2672373

Comments

Paresh Thummar · Accepted Answer · 2014-01-31 05:38:26Z

0

Try this code. This may help you

$json = '{"Fruit":"Apple","Veggies":"Carrot\r\nCelery\r\n\r\nCucumbers"}';
$json = json_decode($json,true);
array_walk($json, function(&$val){$val = html_entity_decode(nl2br($val));});
echo "<pre>";
print_r($json);
echo "</pre>";
exit;

answered Jan 31, 2014 at 5:38

Paresh Thummar

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Criss Anger · Accepted Answer · 2020-12-01 02:06:55Z

0

use

$html = json_decode(nl2br($json,false),true);

Syntax: nl2br(string,xhtml)

With: xhtml Optional. A boolean value that indicates whether or not to use XHTML compatible line breaks:

TRUE- Default. Inserts  

FALSE - Inserts  

with   it make json error.

answered Dec 1, 2020 at 2:06

Criss Anger

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