json_encode returns invalid json format (for me)

Question

<?php
    $a = 'aa,ss';
    $b = explode(',', $a);
    $c = json_encode($b);
    echo $c;

This code is returning:

["aa","ss"]

I need:

{"0":"aa","1":"ss"}

So it is not a valid JSON code - says who? Seems valid to me. — Pekka
– Pekka, Commented Jan 31, 2014 at 23:08
If you need an object, check out the FORCE_OBJECT parameter php.net/json_encode — Pekka
– Pekka, Commented Jan 31, 2014 at 23:09
Oh, I didn't know that. But acctually I need it to be: {0: "aa",1:"ss"} or something simmilar — Dawid Góra
– Dawid Góra, Commented Jan 31, 2014 at 23:10
Thank you Pekka, please write an answer and I will give you rep — Dawid Góra
– Dawid Góra, Commented Jan 31, 2014 at 23:12

Jivan · Accepted Answer · 2014-01-31 23:13:10Z

4

JSON has two equally valid styles of formatting:

Objects
Arrays

What you have is an array. What you seem to think as "valid" is an object.

To output an object with PHP's json_encode(), you can do like this:

json_encode($b, JSON_FORCE_OBJECT);

And you will have what you want.

answered Jan 31, 2014 at 23:13

Jivan

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Comments

MustDie1Bit · Accepted Answer · 2014-01-31 23:13:53Z

2

Use JSON_FORCE_OBJECT at json_encode. Non-associative array output as object:

$a = 'aa,ss';
$b = explode(',', $a);
$c = json_encode($b, JSON_FORCE_OBJECT);
echo $c;

answered Jan 31, 2014 at 23:13

MustDie1Bit

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Comments

Dima · Accepted Answer · 2014-01-31 23:28:29Z

1

$a = 'aa,ss';
$b = explode(',', $a);

$object = new stdClass();
foreach ($b as $key => $value)
{
    $object->$key = $value;
}
$c = json_encode($object);
echo $c;

that will output what you want

edited Jan 31, 2014 at 23:28

answered Jan 31, 2014 at 23:14

Dima

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1 Comment

Dawid Góra Over a year ago

thanks :) but i have already chosen version with JSON_FORCE_OBJECT

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