PHP syntax error in different versions

Question

I sometimes get values from an array like this: $var = array ('key1' => 'value1')['key1']; , so $var should be equal to value1

I run code like this in a server having PHP v5.4.16 , for example, explode ('-', $str)[0]; and it works fine. Now if I transfer this code to another server which uses PHP v5.3.10 I get an error (syntax error): syntax error, unexpected '[' ...

Is this because of the version? (I don't think so because the difference between versions is so small..), or some setting in the server? Can anyone enlighten me?

It has nothing to do with short array syntax but with array dereferencing. — Michal Brašna
– Michal Brašna, Commented Feb 5, 2014 at 13:21
@MichalBrašna That's right. "Function array dereferencing has been added, e.g. foo()[0]". See php.net/manual/en/migration54.new-features.php — Christopher Will
– Christopher Will, Commented Feb 5, 2014 at 13:22
I found this according to @MichalBrašna php.net/manual/en/language.types.array.php#example-89 — Kostas
– Kostas, Commented Feb 5, 2014 at 13:24

Community · Accepted Answer · 2020-06-20 09:12:55Z

1

Yes, it depends on the version of PHP you are running. As PHP docs mentions

As of PHP 5.4 it is possible to array dereference the result of a function or method call directly. Before it was only possible using a temporary variable.

As of PHP 5.5 it is possible to array dereference an array literal.

In PHP 5.3 you would have to use

$exploded = explode('-', $str);
$first = $exploded[0];
// or
list($first,) = explode('-', $str);

In PHP 5.4 and later you can use

$first = explode('-', $str)[0];

edited Jun 20, 2020 at 9:12

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answered Feb 5, 2014 at 13:21

Michal Brašna

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