Django: capturing values in url to generic class view

Question

So I have the url:

url(r'^mousesmall/(?P<name>.*)/$', IDView.as_view()),

and my view is:

class IDView(DetailView):
    model = RNA
    template_name = "home/details.html"

Since I'm using the generic view detailview, how would I pass the name value that's captured in the URL to my detail view?

Peter DeGlopper · Accepted Answer · 2014-02-06 01:06:59Z

1

The base View class that DetailView inherits from sets the args and kwargs to self.args and self.kwargs respectively early in the processing. Since it's a named pattern, it should be in self.kwargs['name'].

answered Feb 6, 2014 at 1:06

Peter DeGlopper

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4 Comments

dl8 Over a year ago

I get name 'self' is not defined.

Peter DeGlopper Over a year ago

Where are you trying to access the parameter? self should definitely be defined inside the view methods - unless you've declared them differently, which would generally be a bad idea.

dl8 Over a year ago

I'm trying to access it within the view, I've added "target_id = self.kwargs['name']" right below my template_name code above.

Peter DeGlopper Over a year ago

That's not how it works - that would be setting a class-level definition. Instead, use it in your get method - or if you're just planning to display it in your template, the get_context_data method.

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