Access nested hash and subroutine

Question

Consider the following code snippet:

#GLOBAL SPACE HERE
{
    #NESTED HERE
    my %hash = (
        key1 => 'A',
        key2 => 'B',
        key3 => 'C',
        key4 => 'D',
    );

    sub test
    {
        #subroutine code goes here
    }
}

How would I access either the hash or the subroutine from the global scope when they are nested within the curly braces?

TLP · Accepted Answer · 2014-02-06 03:36:08Z

2

The hash is lexically scoped to the block (the curly braces), so it can only be accessed from inside that block. The subroutine can be accessed from anywhere, regardless of scope.

edited Feb 6, 2014 at 3:36

answered Feb 6, 2014 at 2:12

TLP

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4 Comments

ysth Over a year ago

the variable is declared at compile time too; the difference is that subroutines are not lexically scoped.

TLP Over a year ago

@ysth The variable cannot be accessed until runtime execution has reached the point in the code where it is declared. The subroutine is available at all points in the code at runtime, regardless of scope.

ysth Over a year ago

re your first point, no: my $x; BEGIN { use strict; $x = 42 } print $x. re your second point, yes, that's what I'm saying you should say instead of "as it is declared at compile time", the latter being not the issue.

TLP Over a year ago

@ysth Well, that's peculiar.

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