Filter two different structured arrays underscore js

Question

I have two arrays:

array1 = [{Name: 'abc', ID: 23},{Name:'xyz', ID: 10},{Name:'def', ID: 12}];
array2 = [10,23];

Resultant array should be part of array 1 whose ID intersects with contents of array2.

Here, the result would be result = [{Name: 'abc', ID: 23},{Name: 'xyz', ID:10}];

Any ideas how I could achieve this using underscore js?

Can you post your code so far? What didn't work? How did you attempt to solve the problem? — elclanrs
– elclanrs, Commented Feb 7, 2014 at 1:25

Adam · Accepted Answer · 2014-02-07 07:12:38Z

3

_.filter(array1, function(item){ return _.contains(array2, item.ID); });

You can use filter and contains.

Try it out here!

edited Feb 7, 2014 at 7:12

answered Feb 7, 2014 at 1:25

Adam

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2 Comments

Rohan Dalvi Over a year ago

Any other way? I am still not getting my result, it returns empty array.

Adam Over a year ago

I was missing a parenthesis. I added a jsfiddle. It works now.

Platinum Azure · Accepted Answer · 2014-02-07 01:26:16Z

1

Assuming your IDs are unique:

var groupedById = _.indexBy(array1, "ID");
var filteredArray = _.map(array2, function (lookupId) {
    return groupedById[lookupId];
});

answered Feb 7, 2014 at 1:26

Platinum Azure

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1 Comment

Platinum Azure Over a year ago

Note that this will return the items in the same order as the list of IDs you're requesting (i.e., the same order as specified by array2). If you would prefer that the ordering in array1 be preserved, you'll want to use a _.filter-based approached.

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