I'm trying to detect string variants: {ext_1} or {ext_1alpha} or {ext_aplpha1}
My regular expression: /{ext_(^[0-9,a-z]+$)}/gi
var arr = str.match(/{ext_(^[0-9,a-z]+$)}/gi);
But this is wrong. How can I solve this problem?
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3 Answers
You have anchors (^ and $) in the middle of the regex where they can't ever match.
Use
/\{ext_([A-Z0-9]+)\}/gi
You also don't want a comma in your character class, unless you want to match actual comma characters in your string. Also, it's a good idea to escape curly braces because they can have special meaning in a regex.
4 Comments
UweB
Notably, the curly brackets also needed escaping, as shown in your changed regex. :)
Tim Pietzcker
@UweB: Not really; they only need to be escaped where they could be misinterpreted (which is not the case here). But it's still good practice to do so.
XTRUST.ORG
Doesn't work. This expression can detect only numbers: /{ext_(\d+)}/gi b and it works but my string can contains numbers or alphanumbers...
Tim Pietzcker
@virtualnobi: Oops. Where did that come from? Thanks for noticing this.
This works-
/{ext_([a-z0-9]+)}/gi
