I am trying to add a value 1.12 between the Min and Max values
Min = 1.3
Max = 6.9
ie
1.3 + 1.12 = 2.42
2.42 + 1.12 = 3.54
till it reaches max value.
What I did is
double sum = 0,BucWidth = 1.12;
sum = min + BucWidth ;
while(sum != max){
sum = sum +BucWidth ;
System.out.println("SUmmmmm" + sum);
}
But it is not stopping when sum reaches max.
Am I doing anything wrong.
Pls Suggest
while (sum <= max) {
sum = sum + BucWidth; // or sum += bucWidth;
System.out.println("SUmmmmm" + sum);
}
You should check if it is less than or equal to, not if it is not equal to in your while condition, since you want to exit the loop when it reaches the limit.
bucWidth instead of BucWidth
1.3 + 5 * 1.12 should == 6.9, it won't == exactly, but rather will be very very close.In general, comparing floating-point numbers for exact equality is asking for trouble unless you have a deep understanding of exactly where and when roundoff will occur. It's safer to use < rather than !=, since the value may never exactly match the one you're expecting.
(This annoyance is one of many reasons that programming languages have int and float as separate datatypes.)
For floating point numbers or long double types it might happen that doing mathematical operations like adding a value to another value might not be equal to a value you assumed as in integer addition operations.
int a=6;
while(sum!=12)
{
sum+=sum;
}
This iterates once.
Consider this
double a=7.4564;
double b=7.4567;
if(a==b){
System.out.println("Both are equal");
}
else{
System.out.println("Both are unequal");
}
Output:-Both are unequal
This is because some number after the decimal can change and so when operations like != are used the numbers have to be exact in all decimal places as used or else the logic won't work. So it is better in your case to use <= instead of != while comparing sum and max.