converting the file format using shell script

Question

i wanted to convert the format of all image files in a folder using the following shell script. My idea is to use the base name of the filename and using the same for naming the file to be converted. I gathered these lines from internet and could not meet my requirement. Thank u all.

for f in *.eps
do
 echo "converting format....."
 filename=`basename ${f}`   
 fbase=`$filename | cut -d'.' -f1`  
 extn = ${fbase}.png  
   convert -geometry 1000x1000 -density 300 -trim ${f} $extn
done

Mark Setchell · Accepted Answer · 2014-02-12 09:36:37Z

1

I think you need something more like this:

#!/bin/bash
for f in *.eps
do  
  new=${f/eps$/png}
  echo Converting $f to $new
  convert -geometry 1000x1000 -density 300 -trim "$f" "$new"
done

Note:

The line commencing "new=" is performing a bash substitution in the variable "f", replacing "eps" at the end of the line (i.e. $) with "png".

edited Feb 12, 2014 at 9:36

answered Feb 12, 2014 at 9:29

Mark Setchell

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3 Comments

Fredrik Pihl Over a year ago

don't use backticks, use $(...) instead.

Fredrik Pihl Over a year ago

and basename can remove the suffix as well, $ echo $(basename test.eps .eps).png

Mark Setchell Over a year ago

Ok, I guess they are more trendy and do have advantages. Thank you - I have updated the answer so my, and the OP's, bad habits don't spread ;-)

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