Converting Perl Regex to PHP

Question

I have the following Regex in PERL which I need to convert to PHP

if ($referrer_url =~ /\.$domain/) { }

I currently have the following in PHP to match it, but I'm not getting the same results:

if (preg_match("/\.$domain/", $referrer_url)) { }

Can anyone tell me if what I have is the same or if I'm mistaken? Thanks!

"I'm not getting the same results" - what is different with your results? — ɴᴀᴛᴇ ᴅᴇᴠ
– ɴᴀᴛᴇ ᴅᴇᴠ, Commented Feb 14, 2014 at 14:24

Community · Accepted Answer · 2023-11-17 19:30:35Z

3

Im just guessing that your $domain probably contains .'s like mysite.com if that is the case you need to use preg_quote on the variable:

if (preg_match("/\.".preg_quote($domain, "/")."/", $referrer_url)) { }

edited Nov 17, 2023 at 19:30

CommunityBot

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answered Feb 14, 2014 at 14:26

Jesper Blaase

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1 Comment

ikegami Over a year ago

Actually, the Perl code is closer to being equivalent to if (preg_match("/\.".$domain."/", $referrer_url)) { }, but it probably should be what you said.

Andrew Mackrodt · Accepted Answer · 2014-02-14 16:43:59Z

2

If $domain is a regular string you may prefer to use strpos to Find the position of the first occurrence of a substring in a string. This would achieve the same result as using preg_quote with the benefit of being easier to read.

if (strpos($referrer_url, ".$domain") !== false) {
}

edited Feb 14, 2014 at 16:43

answered Feb 14, 2014 at 14:32

Andrew Mackrodt

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2 Comments

ikegami Over a year ago

$domain is treated as a regex pattern in the Perl code, this is different, but this probably does what the Perl code should do.

Kenosis Over a year ago

Or just if ( strpos( $referrer_url, ".$domain" ) ) { ... Yes, to my eyes, your solution is more readable than the preg_match() option. +1.

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