Can a variable within a string be declared after the string is declared? [duplicate]

Question

Say I do this:

$string = 'some string with a {$var}';

// Set var after
$var = 'variable'

// String with just set var
$newString = 'Here is my string: ' . $string;
echo $newString;

How would I make it output:

Here is my string: some string with a variable

I could do it with str_replace(), but I was wondering if there was an easier way?

John Conde · Accepted Answer · 2014-02-24 22:30:01Z

7

Based on your example I think sprintf() would work for you:

$string = 'some string with a %s';
$var = 'variable';
$newString = sprintf($string, $var);

answered Feb 24, 2014 at 22:30

John Conde

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1 Comment

ComFreek Over a year ago

+1, one can also use printf() in this case. printf() will directly output the string instead of returning it.

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