Php Variable in loop is not returning the values I want in html

Question

I want to echo 4 lines of code. The variable $x shall be 1,2,3,4 and the variable $y shall be 3,4,5,6.

The $x variable in my loop works fine, the $y however doesn't work like I want it (so it echoes 3,4,5,6 later in HTML)

So my question is: Why is the $y variable not returning 3,4,5,6 in my final HTML code.

for ($x=0; $x<=3;$x++) {
$y=3;
if (${"interferer" .$x} == true) {
  echo "<li><a href='#tabs-$y'>Interferer $x</a></li>";
}
else {
  echo "<!--<li><a href='#tabs-$y'>Interferer $x</a></li>-->";

}
$y++;
}

Alex · Accepted Answer · 2014-02-27 10:46:26Z

1

you're setting $y=3; every time, it will never increment.

Try moving $y=3; outside the for loop.

answered Feb 27, 2014 at 10:46

Alex

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3 Comments

Alex Over a year ago

We all make these mistakes. Glad to help.

Marc Ster Over a year ago

sure, i was waiting for the 10min to pass ;)

Alex Over a year ago

Wow is it 10 mins... I thought it was less than that. Perfect, thank you!

Justinas · Accepted Answer · 2014-02-27 10:46:41Z

1

In every iteration you are making $y=3; and increasing it at the end

answered Feb 27, 2014 at 10:46

Justinas

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Comments

user983983 · Accepted Answer · 2014-02-27 10:47:23Z

1

Y variable is getting initialize at the start of loop everytime.

answered Feb 27, 2014 at 10:47

user983983

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Comments

Pattle · Accepted Answer · 2014-02-27 10:53:39Z

1

You need to update your code so that initialize $y before you enter the for loop

$y=3; //Move outside of for loop
for ($x=0; $x<=3;$x++) {
    if (${"interferer" .$x} == true) {
        echo "<li><a href='#tabs-$y'>Interferer $x</a></li>";
    } else {
        echo "<!--<li><a href='#tabs-$y'>Interferer $x</a></li>-->";

    }
    $y++;
}

How you had it previously mean that $y was getting reset to the value 3 on every iteration of the loop thus destroying the incrementation

answered Feb 27, 2014 at 10:53

Pattle

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Comments

Tzook Bar Noy · Accepted Answer · 2014-02-27 10:50:07Z

0

it is simply because your $y is reset every loop to three, you need to take it out of the loop....

$y=3;  // here :)
for ($x=0; $x<=3;$x++) {
    //$y=3; //not here!
    if (${"interferer" .$x} == true) {
        echo "<li><a href='#tabs-$y'>Interferer $x</a></li>";
    }
    else {
        echo "<!--<li><a href='#tabs-$y'>Interferer $x</a></li>-->";
    }
    $y++;
}

answered Feb 27, 2014 at 10:50

Tzook Bar Noy

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