How to gsub \ in ruby array?

Question

How to remove all \ elements from the array?

Array of size 6:

data =
[
      " \"\"http://www.web1.com\\\"",
      "\"",
      " \"\"https://www.web2.com\\\"",
      "\"",
      " \"\"http://www.web3.com\\\"",
      "\"",
 ]

desired:

 ["www.web1.com", "www.web2.com", "www.web3.com"]

tried :

 data = 
 => [" \"\"http://www.web1.com\\\"", "\"", " \"\"https://www.web2.com\\\"", "\"", " \"\"http://www.web3.com\\\"", "\""] 
2.0.0-p353 :019 > data.each do |d| 
2.0.0-p353 :020 >     d.gsub!(/\+/,'')
2.0.0-p353 :021?>   end
 => [" \"\"http://www.web1.com\\\"", "\"", " \"\"https://www.web2.com\\\"", "\"", " \"\"http://www.web3.com\\\"", "\""] 
2.0.0-p353 :022 >

Kavu · Accepted Answer · 2014-02-28 10:28:40Z

2

Here is how you can get your desired output:

data.map { |e| e.gsub(/["\s\\\/]|(?:https?:\/\/)/,'') }.reject(&:empty?)

You iterate over data array and substitute element's contents that match regexp with ''. Then you just drop empty strings.

Let me explain the regexp a little: [...] means group of characters, we will match any character from a group; | is or operator; (?:) is non-capuring group, so we must match whole https:// or http://; \s means any whitespace character; \\ and \/ are escaped \ and /.

edited Feb 28, 2014 at 10:28

answered Feb 28, 2014 at 9:55

Kavu

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4 Comments

Kavu Over a year ago

Sure, hope that helps.

Nickolay Kondratenko Over a year ago

you can replace select{|e| !e.empty?} with reject{|e| e.empty?}

xdazz Over a year ago

@Kavu What about a url like http://www.htps.com/ or anything else which has htps char in the domain part :)

Kavu Over a year ago

@xdazz yeah, it will totally fail :-D Need to improve my answer.

xdazz · Accepted Answer · 2014-02-28 09:59:08Z

1

This will give you the result you expected.

data.grep(/https?:\/\/([^\\]*)/) {|v| v.match(/https?:\/\/([^\\]*)/)[1] }

But you have to know that \ is used to escape the special char in the string.

"\\" has only one char that is \, "\"" has only one char that is ".

answered Feb 28, 2014 at 9:59

xdazz

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Comments

Severin · Accepted Answer · 2014-02-28 09:54:07Z

0

You can gsub all \ by doing:

your_string.gsub('\','')

answered Feb 28, 2014 at 9:54

Severin

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Comments

hirolau · Accepted Answer · 2014-02-28 10:33:40Z

0

data.grep(/http/){|x|x.delete '\\\" '}

edited Feb 28, 2014 at 10:33

answered Feb 28, 2014 at 10:27

hirolau

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