Matching multiple words Regex , python

Question

i need to match a pattern from a string. The string is variable so i need to develop some amount of variability in it .
What i need to do is extract words occurring with "layout" and they occur in 4 different manners

1 word -- layout` eg: hsr layout

2words -- layout eg: golden garden layout

digit-word -- layout eg: 19th layout

digit-word word --layout eg:- 20th garden layout

It can be seen that i need the digits field to be optional. a single regex must do it. here's what i did:

import re
p = re.compile(r'(?:\d*)?\w+\s(?:\d*)?\w+l[ayout]*')
text = "opp when the 19th hsr layut towards"
q = re.findall(p,text)

i need 19th hsr layout in this expression. but the above code returns none. What is the problem with my code above?

Some string examples are:

str1 = " 25/4 16th june road ,watertank layout ,blr"  #extract watertank layout 
str2 = " jacob circle 16th rusthumbagh layout , 5th cross" #extract 16th rustumbagh layout
str3 = " oberoi splendor garden blossoms layout , 5th main road"  #extract garden blossoms layout
str4 = " belvedia heights , 15th layout near Jaffrey gym" #extract 15th layout

words that occur with the word layout.. 4 conditions given above.. — Hypothetical Ninja
– Hypothetical Ninja, Commented Mar 5, 2014 at 5:08
well ,yes.. i accounted for it using l[ayout]* for any mistakes in text.. — Hypothetical Ninja
– Hypothetical Ninja, Commented Mar 5, 2014 at 5:09

falsetru · Accepted Answer · 2014-03-05 05:48:08Z

2

Use r'(?:\w+\s+){1,2}layout' as I commented:

>>> import re
>>> p = re.compile(r'(?:\w+\s+){1,2}layout')
>>> p.findall(" 25/4 16th june road ,watertank layout ,blr")
['watertank layout']
>>> p.findall(" jacob circle 16th rusthumbagh layout , 5th cross")
['16th rusthumbagh layout']
>>> p.findall(" oberoi splendor garden blossoms layout , 5th main road")
['garden blossoms layout']
>>> p.findall(" belvedia heights , 15th layout near Jaffrey gym")
['15th layout']

{1,2} is used to match at most 2 words.

answered Mar 5, 2014 at 5:48

falsetru

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falsetru Over a year ago

@Sword, \w matches word character. Word characters include alphabets, digits and _.

Bibhas Debnath · Accepted Answer · 2014-03-05 05:32:14Z

1

This seems to work -

import re

l = [" 25/4 16th june road ,watertank layout ,blr",
" jacob circle, 16th rusthumbagh layout , 5th cross",
" oberoi splendor , garden blossoms layout , 5th main road",
" belvedia heights , 15th layout near Jaffrey gym",]

for ll in l:
    print re.search(r'\,([\w\s]+)layout', ll).groups()

Output:

('watertank ',)
(' 16th rusthumbagh ',)
(' garden blossoms ',)
(' 15th ',)

answered Mar 5, 2014 at 5:32

Bibhas Debnath

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